Dev Stack Source

Example: cm to inch 1 cm = 0.3937 inch

Example: dollars in euros Stonks in european

Answer : According to the openssh docs, the ssh client, which will usually prompt for a password on the command line, will try to show a GUI dialog for the user to enter his password, if SSH_ASKPASS and DISPLAY environment variables are set. On windows however, this is not properly supported yet, as the needed ssh_askpass binary is missing, and also because this seems still pretty X11 oriented. Git for windows however seemed to get it working properly. Of course, if you are just interested in entering your password on the command line, make sure the variables are unset. With the information you provided, it is however impossible to answer why the variable was set in the first place. If you need the DISPLAY variable set because you want to use VcXsrc or another X-Server in Windows 10 the workaround is to add the host you want to connect to your known_hosts file. This can be done by calling ssh-keyscan -t rsa host.example.com | Out-File ~/.ssh/known_hosts -Append -Encoding ASCII;

Answer : It seems this has been reported to the maintainers already. Now, as a consumer of an open source software, you may: wait for them to fix (or not fix) the problem be cool and submit a PR to fix it for them :) Here are all the references to componentWillReceiveProps in the repo find a new package to use Ultimately, this isn't an error related to your software, but the dependencies it relies on. It isn't really your responsibility to fix those. If your app runs, it'll be fine. Warnings from react-dom.development.js won't appear in production. Use getDerivedStateFromProps instead of componentWillReceiveProps For example: Before: // Before class ExampleComponent extends React.Component { state = { isScrollingDown: false, }; componentWillReceiveProps(nextProps) { if (this.props.currentRow !== nextProps.currentRow) { this.setState({ isScrollingDown: nextProps.currentRow > this.props.currentRow, }); } } } After

Example 1: what are the types of positioning in css The types of positioning in CSS are- 1 ) static : this is the default value. 2 ) sticky : the element is positioned based on the user's scroll position. 3 ) fixed : the element is positioned related to the browser window. 4 ) relative : the element is positioned relative to its normal position. 5 ) absolute : the element is positioned absolutely to its first positioned parent. Example 2: css position h2 .pos_left { position : relative ; left : -20 px ; } h2 .pos_right { position : relative ; left : 20 px ; } Example 3: position relative and absolute difference in css <div class=”parent”> <div class=”box” id=”one”>One</div> <div class=”box” id=”two”>Two</div> <div class=”box” id=”three”>Three</div> <div class=”box” id=”four”>Four</div></div>

Answer : If value is associative array, such code will work fine: var value = { "aaa": "111", "bbb": "222", "ccc": "333" }; var blkstr = []; $.each(value, function(idx2,val2) { var str = idx2 + ":" + val2; blkstr.push(str); }); console.log(blkstr.join(", ")); <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> (output will appear in the dev console) As Felix mentioned, each() is just iterating the array, nothing more. Converting From Array to String is So Easy ! var A = ['Sunday','Monday','Tuesday','Wednesday','Thursday'] array = A + "" That's it Now A is a string. :) You can use .toString() to join an array with a comma. var array = ['a', 'b', 'c']; array.toString(); // result: a,b,c Or, set the separator with array.join('; '); // r

Example 1: how to change the color of the hr tag in html <style > hr { height : 1 px ; background-color : #ccc ; border : none ; } </style> Example 2: html horizontal line style <!-- HTML --> <!-- You can change the style of the horizontal line like this : --> <hr style= "width:50%" , size= "3" , color= black > <!-- Or like this : --> <hr style= "height:2px; width:50%; border-width:0; color:red; background-color:red" > Example 3: how to style an hr tag /* Red border */ hr .new1 { border-top : 1 px solid red ; } /* Dashed red border */ hr .new2 { border-top : 1 px dashed red ; } /* Dotted red border */ hr .new3 { border-top : 1 px dotted red ; } /* Thick red border */ hr .new4 { border : 1 px solid red ; } /* Large rounded green border */ hr .new5 { border : 10 px solid green ; border-radius : 5 px

Example 1: horizontal align tailwind <div class= "flex items-center justify-center h-screen" > <div class= "bg-indigo-800 text-white font-bold rounded-lg border shadow-lg p-10" > Centered Content </div> </div> Example 2: tailwind tect align left Class Properties text-left text-align : left ; text-center text-align : center ; text-right text-align : right ; text-justify text-align : justify ; Example 3: tailwind text justified <p class= "text-justify ..." >Lorem ipsum dolor sit amet ...</p>

Example 1: cm to inches 1 cm = 0.393701 inch Divide the cm value by 2.54 . Example 2: cm to inches const cm = 1 ; console . log ( ` cm: ${ cm } = in: ${ cmToIn ( cm ) } ` ) ; function cmToIn ( cm ) { var in = cm / 2.54 ; return in ; }

Answer : It is definitely for someone who already knows the subject and is looking for a different perspective. It is not advanced and it is not introductory, more a supplement. It is also sloppy and very hard to follow for someone who does not know the subject. The praises are from people who know the subject and like the presentation and a few things not easily found elsewhere. Overall, it is not a good book in my opinion. I think Differential Forms in Algebraic Topology is well written. However, it is written in a way a master teaches a student: There are no loss of detail, no fancy language, and explicit examples are everywhere. The student is supposed to emulate Bott's proof writing style, to criticize it, to tease it and understand every detail of it. When I read it I often find questions I would ask myself was discussed by him in very detail. But I am also aware that this is my second or third time reading the book; when I read it the first time my feeling was quite

Answer : From what you describe, it seems you have UTF-8 data that was originally stored as Latin-1 and then not converted correctly to UTF-8. The data is recoverable; you'll need a MySQL function like convert(cast(convert(name using latin1) as binary) using utf8) It's possible that you may need to omit the inner conversion, depending on how the data was altered during the encoding conversion. After i searched about an hour or two for this answer. I needed to migrate a old tt_news db from typo into a new typo3 version. I already tried convert the charset in the export file and import it back, but didn't get it working. Then i tried the answer above from ABS and startet a update on the table: UPDATE tt_news SET title=convert(cast(convert(title using latin1) as binary) using utf8), short=convert(cast(convert(short using latin1) as binary) using utf8), bodytext=convert(cast(convert(bodytext using latin1) as binary) using utf8) WHERE 1 You can also convert im

Answer : It shows that the assembly you referenced in the project has different version(4.0.0.1) as what you have in web.config(4.0.0.0). Please check that the referenced assembly for System.Web.Mvc is the same as written in the web.config. If not then add reference to the appropriate assembly. Right click References -> Add Reference -> ... Install Nuget Package Microsoft.AspNet.Mvc for all the project referencing System.Web.Mvc dll Example: Install-Package Microsoft.AspNet.Mvc

Answer : Amplitude is an int value. Its The strength of the vibration. This must be a value between 1 and 255, or DEFAULT_AMPLITUDE which is -1. You can use it as VibrationEffect.DEFAULT_AMPLITUDE More details here with kotlin private fun vibrate(){ val vibrator = context.getSystemService(Context.VIBRATOR_SERVICE) as Vibrator if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) { vibrator.vibrate(VibrationEffect.createOneShot(200, VibrationEffect.DEFAULT_AMPLITUDE)) } else { vibrator.vibrate(200) } } You can use this for haptic feedback (vibration): view.performHapticFeedback(HapticFeedbackConstants.LONG_PRESS); There are other constants available in HapticFeedbackConstants like VIRTUAL_KEY , KEYBOARD_TAP ...

Example: c++ replace substrings using namespace std ; string ReplaceAllSubstringOccurrences ( string sAll , string sStringToRemove , string sStringToInsert ) { int iLength = sStringToRemove . length ( ) ; size_t index = 0 ; while ( true ) { /* Locate the substring to replace. */ index = sAll . find ( sStringToRemove , index ) ; if ( index == std :: string :: npos ) break ; /* Make the replacement. */ sAll . replace ( index , iLength , sStringToInsert ) ; /* Advance index forward so the next iteration doesn't pick it up as well. */ index += iLength ; } return sAll ; } // EXAMPLE: in usage string sInitialString = "Replace this, and also this, don't forget this too" ; string sFinalString = ReplaceAllSubstringOccurrences ( sInitialString , "this" , "{new word/phrase}" ) ; cout << "[sInitialString->" << sInit

Answer : Disable the hibernation mode and Fast Boot in Windows. Open command prompt as administrator and execute : powercfg /h off Open the legacy version of the Windows Control Panel (not the modern version). Select Energy Settings , enable show hidden settings and uncheck Fast Boot. After having done this - shutdown the computer completely - do NOT reboot. Boot into the BIOS and select Ubuntu as the default operating system to boot. Update : In case there is no Ubuntu entry to be found in the BIOS / UEFI settings, re-install the GRUB boot loader to your Ubuntu installation in EFI mode. Boot from the Ubuntu installation media - open a terminal and execute: sudo mount /dev/sdXXX /mnt sudo mount /dev/sdXX /mnt/boot/efi for i in /dev /dev/pts /proc /sys /run; do sudo mount -B $i /mnt$i; done sudo chroot /mnt grub-install /dev/sdX update-grub Note: sdX = disk | sdXX = efi partition | sdXXX = system partition To identify the partition numbers use G

Example 1: string palindrome in python n = input ( "Enter the word and see if it is palindrome: " ) #check palindrome if n == n [ :: - 1 ] : print ( "This word is palindrome" ) else : print ( "This word is not palindrome" ) Example 2: palindrome python # A palindrome is a word , number , phrase , or other sequence of characters which reads the same backward as forward . # Ex : madam or racecar . def is_palindrome ( w ) : if w == w [ :: - 1 ] : # w [ :: - 1 ] it will reverse the given string value . print ( "Given String is palindrome" ) else : print ( "Given String is not palindrome" ) is_palindrome ( "racecar" )

Example: strcpy /* strcpy example */ # include <stdio.h> # include <string.h> int main ( ) { char str1 [ ] = "Sample string" ; char str2 [ 40 ] ; char str3 [ 40 ] ; strcpy ( str2 , str1 ) ; //str1 copies to str2 strcpy ( str3 , "copy successful" ) ; printf ( "str1: %s\nstr2: %s\nstr3: %s\n" , str1 , str2 , str3 ) ; return 0 ; }

Example: c program for prims algorithm # include <stdio.h> # include <conio.h> int a , b , u , v , n , i , j , ne = 1 ; int visited [ 10 ] = { 0 } , min , mincost = 0 , cost [ 10 ] [ 10 ] ; void main ( ) { clrscr ( ) ; printf ( "\n Enter the number of nodes:" ) ; scanf ( "%d" , & n ) ; printf ( "\n Enter the adjacency matrix:\n" ) ; for ( i = 1 ; i <= n ; i ++ ) for ( j = 1 ; j <= n ; j ++ ) { scanf ( "%d" , & cost [ i ] [ j ] ) ; if ( cost [ i ] [ j ] == 0 ) cost [ i ] [ j ] = 999 ; } visited [ 1 ] = 1 ; printf ( "\n" ) ; while ( ne < n ) { for ( i = 1 , min = 999 ; i <= n ; i ++ ) for ( j = 1 ; j <= n ; j ++ ) if ( cost [ i ] [ j ] < min ) if ( visited [ i ] != 0 ) { min = cost [ i ] [ j ] ; a = u = i ; b