Convert A Numpy.ndarray To String(or Bytes) And Convert It Back To Numpy.ndarray

Answer :

You can use the fromstring() method for this:

arr = np.array([1, 2, 3, 4, 5, 6])
ts = arr.tostring()
print(np.fromstring(ts, dtype=int))

>>> [1 2 3 4 5 6]

Sorry for the short answer, not enough points for commenting. Remember to state the data types or you'll end up in a world of pain.

Note on fromstring from numpy 1.14 onwards:

sep : str, optional

The string separating numbers in the data; extra whitespace between elements is also ignored.

Deprecated since version 1.14: Passing sep='', the default, is deprecated since it will trigger the deprecated binary mode of this function. This mode interprets string as binary bytes, rather than ASCII text with decimal numbers, an operation which is better spelt frombuffer(string, dtype, count). If string contains unicode text, the binary mode of fromstring will first encode it into bytes using either utf-8 (python 3) or the default encoding (python 2), neither of which produce sane results.

If you use tostring you lose information on both shape and data type:

>>> import numpy as np
>>> a = np.arange(12).reshape(3, 4)
>>> a
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11]])
>>> s = a.tostring()
>>> aa = np.fromstring(a)
>>> aa
array([  0.00000000e+000,   4.94065646e-324,   9.88131292e-324,
         1.48219694e-323,   1.97626258e-323,   2.47032823e-323,
         2.96439388e-323,   3.45845952e-323,   3.95252517e-323,
         4.44659081e-323,   4.94065646e-323,   5.43472210e-323])
>>> aa = np.fromstring(a, dtype=int)
>>> aa
array([ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11])
>>> aa = np.fromstring(a, dtype=int).reshape(3, 4)
>>> aa
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11]])

This means you have to send the metadata along with the data to the recipient. To exchange auto-consistent objects, try cPickle:

>>> import cPickle
>>> s = cPickle.dumps(a)
>>> cPickle.loads(s)
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11]])

Imagine you have a numpy array of integers (it works with other types but you need some slight modification). You can do this:

a = np.array([0, 3, 5])
a_str = ','.join(str(x) for x in a) # '0,3,5'
a2 = np.array([int(x) for x in a_str.split(',')]) # np.array([0, 3, 5])

If you have an array of float, be sure to replace int by float in the last line.

You can also use the __repr__() method, which will have the advantage to work for multi-dimensional arrays:

from numpy import array
numpy.set_printoptions(threshold=numpy.nan)
a = array([[0,3,5],[2,3,4]])
a_str = a.__repr__() # 'array([[0, 3, 5],\n       [2, 3, 4]])'
a2 = eval(a_str) # array([[0, 3, 5],
                 #        [2, 3, 4]])